abcd is a rectangle length ab= 3x+2 units , breathe Bc= y-2 , cd= x+10, da= 3y-10, then find the length of the diagonal
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Answered by
8
heya,
we know,
opposite sides of a rectangle are equal.
for detailed solution refer to given attachment please
we know,
opposite sides of a rectangle are equal.
for detailed solution refer to given attachment please
Attachments:
Answered by
11
As it is a Rectangle,
Length = ab = cd
Breadth = bc = ad
________________
Length,
ab = cd
3x + 2 = x + 10
3x - x = 10-2
2x = 8
x = 8/2
x = 4
________
Breadth,
bc = ad
y- 2 = 3y - 10
-2 + 10 = 3y - y
8 = 2y
8/2 = y
4 = y
______________
Length = 3x + 2
= 3(4) + 2
= 12 + 2
= 14 units
Breadth = y - 2
= 4 - 2
= 2 units
______________________
By Pythagoras theorem,
length + breadth = diagonal
14² + 2² = diagonal²
196 + 4 = diagonal²
200 = diagonal²
√200 = Diagonal
10√2 units = diagonal
_________________
Length of Diagonal = 10√2 units
i hope this will help you
-by ABHAY
Length = ab = cd
Breadth = bc = ad
________________
Length,
ab = cd
3x + 2 = x + 10
3x - x = 10-2
2x = 8
x = 8/2
x = 4
________
Breadth,
bc = ad
y- 2 = 3y - 10
-2 + 10 = 3y - y
8 = 2y
8/2 = y
4 = y
______________
Length = 3x + 2
= 3(4) + 2
= 12 + 2
= 14 units
Breadth = y - 2
= 4 - 2
= 2 units
______________________
By Pythagoras theorem,
length + breadth = diagonal
14² + 2² = diagonal²
196 + 4 = diagonal²
200 = diagonal²
√200 = Diagonal
10√2 units = diagonal
_________________
Length of Diagonal = 10√2 units
i hope this will help you
-by ABHAY
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