ABCD is a rectangle of dimensions 21cm*14cm. A semicircle is drawn with BC as diameter. Find the and perimeter of the shaded region.
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sanjanaSK:
10th class maths board question number30 right
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Answers
Answered by
158
area of the shaded region= area of rectangle-area of semicircle
=l*b - (pi*r^2)/2
=21*14 - (pi*7^2)/2
=294 - (22/7*49)/2
=294 - 22*7/2
=294 - 77
=217 cm^2 answer
perimeter of shaded region = perimeter of rectangle- perimeter of semicircle
=70 - 22
=48 cm answer
=l*b - (pi*r^2)/2
=21*14 - (pi*7^2)/2
=294 - (22/7*49)/2
=294 - 22*7/2
=294 - 77
=217 cm^2 answer
perimeter of shaded region = perimeter of rectangle- perimeter of semicircle
=70 - 22
=48 cm answer
Answered by
46
Answer:
Step-by-step explanation:
Perimeter of shaded region=AB+BC+CD+Circumference of semicircle=21+14+21+22/7x7
= 78cm?
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