ABCD is a rectangle taking AD as a diameter is semicircle A is drawn which intersects diagonal BD at x .If AB=12 cm AB 5 cm then BD f B x find.
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Answered by
1
Answer:
ANSWER
Given−
ABCDisarectangleandAXDisasemicirclewithinABCD.
ThediagonalBDintersectsAXDatX.
AB=12cm,BD=9cm.
Tofindout−
thevaluesofBD=?BX=?.
Solution−
Actually,BDisatangenttothecirclewithADasdiameter
andDXisasecanttothesamecircle.
ABintersectsthegivencircleatX.
Also∠DAB=90
o
sinceABCDisarectangle.
So,byPytagorastheorem,wehave
BD=
AD
2
+AB
2
cm=
9
2
+12
2
cm=15cm.
Again,byapplyingtangent−secantrule,wehave
BD×BX=AB
2
⟹BX=
BD
AB
2
=
15
12
2
cm=9.6cm.
∴Ans−OptionC
Answered by
1
Answer:
Just chill bro it very simple qbcdefghijklmnopqrstuvwxyz ye ABC C bhot easy hai
Step-by-step explanation:
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