Math, asked by suryavanshis541, 10 months ago

ABCD is a rectangle taking AD as a diameter is semicircle A is drawn which intersects diagonal BD at x .If AB=12 cm AB 5 cm then BD f B x find.​

Answers

Answered by trinoyjyotipegu
1

Answer:

ANSWER

Given−

ABCDisarectangleandAXDisasemicirclewithinABCD.

ThediagonalBDintersectsAXDatX.

AB=12cm,BD=9cm.

Tofindout−

thevaluesofBD=?BX=?.

Solution−

Actually,BDisatangenttothecirclewithADasdiameter

andDXisasecanttothesamecircle.

ABintersectsthegivencircleatX.

Also∠DAB=90

o

sinceABCDisarectangle.

So,byPytagorastheorem,wehave

BD=

AD

2

+AB

2

cm=

9

2

+12

2

cm=15cm.

Again,byapplyingtangent−secantrule,wehave

BD×BX=AB

2

⟹BX=

BD

AB

2

=

15

12

2

cm=9.6cm.

∴Ans−OptionC

Answered by Pa4483
1

Answer:

Just chill bro it very simple qbcdefghijklmnopqrstuvwxyz ye ABC C bhot easy hai

Step-by-step explanation:

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