Question

ABCD is a rectangle. The diagonals AC & BD intersect each other at O. Find the value of y if OA = y+4 and OC=2y-3​

Answer 1

$\large \green{ \fcolorbox{gray}{black}{ ☑ \: \textbf{Verified \: answer}}}$

$\large\fbox { \sf Diagram}$

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Understanding the question content :

• A rectangle ABCD in that figure 2 diagonals AC and BD intersecting each other at a point O . For solving this question , use the properties of  rectangles .

Solution :

AC = BD ( Diagonals bisect each other )

→ OA = y + 4 and OC = 2y - 3 ( given )

→ ( y + 4 ) = ( 2y - 3 )

→  4 + 3 = 2y - y

→ 7 = y

Therefore , the value of y = 7

Remarks from the answerer :

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Answer 2

Step-by-step explanation:

AC = BD ( Diagonals bisect each other )

→ OA = y + 4 and OC = 2y - 3 ( given )

→ ( y + 4 ) = ( 2y - 3 )

→ 4 + 3 = 2y - y

→ 7 = y

Therefore , the value of y = 7