Chemistry, asked by itsbrainlybiswa, 6 months ago

ABCD is a rectangle. The line through C perpendicular to the diagonal AC intersects AB, AC (both produced) at E and F respectively. Prove that BEFD is a cyclic quadrilateral.


mathsaryabhattta k log plzz answer it

Answers

Answered by syedali84242
3

Answer:

Let AB be the chord of the given circle with centre O and a radius of 10 cm.

Then AB =16 cm and OB = 10 cm

From O, draw OM perpendicular to AB.

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ BM = (162) cm=8 cm

In the right ΔOMB, we have:

OB2 = OM2 + MB2 (Pythagoras theorem)

⇒ 102 = OM2 + 82

⇒ 100 = OM2 + 64

⇒ OM2 = (100 - 64) = 36

⇒ OM=36−−√ cm=6 cm

Hence, the distance of the chord from the centre is 6 cm.

May be it is help to you

Answered by BubblySnowFake
0

In ΔADE,

∠EAD+∠BAF=90

o

and

∠EAD+∠BAF=90

o

⇒∠EDA=∠BAF

AF

DE

=

BF

AE

BF

AF

=

AE

DE

=

3

5

....(1)

similarly ΔCFB:ΔDEC

BF

CE

=

CF

DE

BF

CF

=

CE

DE

=

7

5

...(2)

adding (1) and (2)

BF

AF+CF

=

21

50

BF

AC

=

21

50

BF

10

=

21

50

⇒BF=4.2

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