Question

ABCD is a rectangle where the diagonals AC and BD
intersect at P. If BPC =116°, calculate
a)BAP
b)ADP.

Answer 1

a rectangle, diagonals are of equal length and bosect each other ⇒AP=BP

Now ∠APB+∠BPC=180

o

(linear)

⇒∠APB=56

o

and ∠ABP=∠BAP(AP=BP)

⇒ In ΔABP, angle sum is 180

o

⇒∠BAP=

2

180−56

=62

Now ∠APD=124

o

⇒∠ADP=

2

180−124

=28

o