Question

ABCD is a rectangle whose diagonal AC and BD intersect each other at O . If angle OAB=28 Degree, find angle OBC

Answer 1

Answer:

Step-by-step explanation:

EACH AND EVERY ANGLES IN A RECTANGLE IS EQUAL TO 90°.

DIAGONALS OF RECTANGLE CUTS EACH OTHER INTO THEIR HALF.

SO,

AO = BO.

WE KNOW THAT,

ANGLES OPPOSITE TO EQUAL SIDES ARE ALSO EQUALS.

SO,

<OBA = <OAB

<OBA = 46° ___ (1)

WE KNOW,

<ABC = <OBA + <OBC

90° = <46° + <OBC

<OBC = 44°.

Hope it's helpful

Answer 2

$\huge\bold\red{Hey!}$

Plz refer to the attachment..