Question

ABCD is a rectangle whose diagonal AC and BD intersect each other at O . If angle OAB 28° FIND angle angle OBC

Answer 1

the angle obc=90-28=62
as the sum of the angles are complementary.

Answer 2

Answer:

The angle OBC = 62°

Step-by-step explanation:

Given data

ABCD  is a rectangle with diagonals AC and BC

And angle OAB = 28°  

here we need to find angle OBC  

In a rectangle diagonals are equal and bisects each other

⇒ in rectangle ABCD , OA = OB

⇒ ∠OAB  = ∠OBA =  28°   [ ∵ opposite angles ( ∠OAB , ∠OBA) of the equal sides (OA and OB) are equal ]

⇒ we know that measure of each angle in a rectangle = 90°

⇒  ∠ ABC =  90°  

⇒ ∠ABO + ∠OBC = 90°  

⇒   28°  +  ∠OBC  = 90°  

⇒   ∠OBC  = 90° - 28°

⇒  ∠ OBC  =  62°