ABCD is a rectangle whose diagonals AC and BD intersect at O if angle A is equal to 32 degree find angle OCD
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Answered by
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Step-by-step explanation:
EACH AND EVERY ANGLES IN A RECTANGLE IS EQUAL TO 90°.
DIAGONALS OF RECTANGLE CUTS EACH OTHER INTO THEIR HALF.
SO,
AO = BO.
WE KNOW THAT,
ANGLES OPPOSITE TO EQUAL SIDES ARE ALSO EQUALS.
SO,
<OBA = <OAB
<OBA = 46° ___ (1)
WE KNOW,
<ABC = <OBA + <OBC
90° = <46° + <OBC
<OBC = 44°.
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