Question

abcd is a rectangle whose diagonals ac and bd intersect at o.if angle AOB=114° find angle OAB,angle OAD,angle OCD​

Answer 1

Answer

Since in a rec diagonal are equal and bisect each other

∴OD=OA

and ∠S opp to equal sides are equal

∴∠1=x

Now, In ΔODA

∠DOA=70

0

(vertically opp. ∠S)

x+∠1+70=180

0

(∠ sum prop)

and ∠1=x

∴x+x+70=180

2x=110

x= 110/2

x=55°

=> <ODA = 55°