Question

ABCD is a rectangle whose diagonals AC and BD intersect at o. if

Answer 1

Answer:

EACH AND EVERY ANGLES IN A RECTANGLE IS EQUAL TO 90°.

DIAGONALS OF RECTANGLE CUTS EACH OTHER INTO THEIR HALF.

SO,

AO = BO.

WE KNOW THAT,

ANGLES OPPOSITE TO EQUAL SIDES ARE ALSO EQUALS.

SO,

<OBA=<OAB

<OBA = 46°

WE KNOW,

<ABC = <OBA + <OBC

90° <46° + <OBC

<OBC = 44°.