ABCD is a rectangle whose length and breadth are 26 cm and 15 CM respectively adf is a triangle such that it is perpendicular to a d and e f is equals to 8 cm calculate the area of shaded portion I don't have the picture how to click a picture in brainly
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Area of Triangle BCD =1/2*20*15=150
BD= sqrt (20^2+15^2)=25
also area of BCD can be determined as 1/2* BD* height from C to BD
lets height from C meets BD at X
Area of triangle BCX will be
1/2* BD* CX =150
=>1/2*25* CX=150
=>CX=300/25=12
Now, BX= sqrt (20^2-12^2)=16
So, area of shaded region will be
1/2* BX*CX=1/2*16*12=96
BD= sqrt (20^2+15^2)=25
also area of BCD can be determined as 1/2* BD* height from C to BD
lets height from C meets BD at X
Area of triangle BCX will be
1/2* BD* CX =150
=>1/2*25* CX=150
=>CX=300/25=12
Now, BX= sqrt (20^2-12^2)=16
So, area of shaded region will be
1/2* BX*CX=1/2*16*12=96
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