Question

ABCD is a rectangle whose three vertices are A(4,0), C(4,3) and D(0,3). Find the length of one its diagonal. ​

Answer 1

Answer:

From the diagram we can see that AB =4 units, BC =3 units

Using Pythagoras theorem,

AC ^2 =AB^2 +BC ^2

=4^2+3^2

AC^2 =16+9=25

Taking square root on both the sides, we get

AC =5 units.

Answer 2

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The given vertices are B (4, 0), C (4, 3) and D (0, 3).Here, BD one of the diagonals So.

➟BD = √(4-0)² + (0-3)²

➟√(4²) + (-3²)

➟√16 + 9

➟√25

➟5

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