Question

ABCD is a rectangle whose three vertices are B (0,4) C (4,3) and D(0,3)find the length of one of its diagonal
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Answer 1

Answer:

1 unit( or unity)

Step-by-step explanation:

In the rectangle ABCD, AC and BD are the diagonals of same length.

Using distance formula we can find the distance between B and D.

 ⇒ BD = √(0 - 0)² + (4 - 3)²

            = √0 + 1²

            = √1

             = 1

Length of each diagonal is 1 unit.

It could be 5, if point D is (3 , 0). Using same, distance formula,

BD = √(0 - 3)² + (4 - 0)² = 5 unit

Answer 2

Answer:

Given :-

• ABCD is a rectangle whose three vertices are B(0 , 4) , C(4 , 3) , D(0 , 3).

To Find :-

• What is the length of one of its diagonal.

Solution :-

ABCD is a rectangle.

BD is one of a diagonal

Given :

• B(0 , 4)
• C(4 , 3)
• D(0 , 3)

Then, according to the question,

↦ $\sf BD =\: \sqrt{{(0 - 0)}^{2} + {(4 - 3)}^{2}}$

↦ $\sf BD =\: \sqrt{{(0)}^{2} + {(1)}^{2}}$

↦ $\sf BD =\: \sqrt{0 \times 0 + 1 \times 1}$

↦ $\sf BD =\: \sqrt{0 + 1}$

➠ $\sf\bold{\red{BD =\: 1}}$

$\therefore$ The length of the diagonal is 1 unit .