Question

ABCD is a rectangle whose three vertices are b(12 0) c( 12 5) and d (0 5). find the length of one of its diagonals.
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Answer 1

Given:-

• ABCD is a Rectangle.
• Point B = (12,0)
• Point C = (12,5)
• Point D = (0,5)

To Find:-

• The length of one of its diagonals.

Solution:-

Diagonals of Rectangle ABCD are AC & BD

$\boxed{\sf{Distance\; between\;two\;points = \sqrt{(x_2-x_1)²+(y_2-y_1)²}}}$

$→\;{\sf{BD = \sqrt{(0-12)²+(5-0)²}}}$

$→\;{\sf{BD = \sqrt{(-12)²+(5)²}}}$

$→\;{\sf{BD = \sqrt{144+25}}}$

$→\;{\sf{BD = \sqrt{169}}}$

$→\;{\sf{BD = \sqrt{13²}}}$

$→\;{\red{\bold{BD = 13}}}$

• Length of one of it's diagonal is 13 units.

$\Large{✓}$

Hope It Helps You ✌️

Answer 2

Step-by-step explanation:

13 is the answer

I hope this will help you