Question

ABCD is a rectangle whose three vertices are B(4,0),C(4,3) and D(0,3). The length of one of its diagonals is

Answer 1

Answer:

From the diagram we can see that AB = 4

Units, BC = 3units

Using Pythagoras theorem

AC² = AB² + BC²

= 4² + 3²

AC² = 16 + 9 = 25

AC = 5 units

Answer 2

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The given vertices are B (4, 0), C (4, 3) and D (0, 3).Here, BD one of the diagonals.

So,

$BD = \sqrt{ {(4 - 0)}^{2} + {(0 - 3)}^{2} }$

$= \sqrt{ {4}^{2} + {3}^{2} }$

$= \sqrt{25}$

$BD = 5$

Hence, the length of the diagonal is 5 units.

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