Math, asked by uknownuser123, 8 months ago

ABCD is a rectangle with a ngle BAC =32° determine angle DBC​

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Answered by Anonymous
0

Answer:

32°

Step-by-step explanation:

angle DBC = 32°

angle AOB = 90 (properties of rectangle)

therefore, angle AOB + BAC + OBA = 180°(right angle triangle)

angle ABO = 180 - (90 + 32 ) =58°

angle DBC + ABO = 90° (angle in rectangle is always 90°)

hence angle DBC = 90 - 58 = 32 °

Answered by anushkas20
2

Answer:

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