ABCD is a rectangle with a ngle BAC =32° determine angle DBC
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Answer:
32°
Step-by-step explanation:
angle DBC = 32°
angle AOB = 90 (properties of rectangle)
therefore, angle AOB + BAC + OBA = 180°(right angle triangle)
angle ABO = 180 - (90 + 32 ) =58°
angle DBC + ABO = 90° (angle in rectangle is always 90°)
hence angle DBC = 90 - 58 = 32 °
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