ABCD is a rectangle with AB = 16 cm and BC = 10 cm. If E, F and G are mid points of AC, DE and AF respectively, what is the area of AADG?
O 5 cm O 10 cm2 O 8 cm2 O 16 cm
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Answer:
area of rectangle ABCD= 16×10=160
THEN ar of ACD= 160÷2= 80
ar of ADE = 80÷2= 40
ar of ADF= 40÷2= 20 &
ar of ADG=20÷2= 10
ANS = 10 CM square
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