Question

abcd is a rectangle with angle b a c=32°,find angle d b c​

Answer 1

Let ABCD be a rectangle whose diagonals meet at O

Now angle BAC=32
So angle ACD=32(alt. Interior angles)

Now angleDCB=90(angle in a rectangle)

So angleACB=90-32=68

Now as the diagnals bisect each other in a rectangle,
OB=OC
so angle OCB=angleOBC(angles opposite equal sides are equal)


So angle DBC=68