ABCD is a rectangle with angle BAC = 28° . Find the measure of angle DBC
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Answer:
ABCD is a rectangle
all the angle=90
BAC+CAD=90
28+CAD=90
CAD=90-28
CAD=62
let the diagonal AC and BD bisect each other at point O
AOD=90
(diagonals of rect. are perpendicular bisector of each other)
In triangle AOD
A+O+D=180
(sum of all angle of a triangle is 180)
62+90+D=180
152+D=180
D=180-152
D=28
ADB=28
ADB=DBC
(alternative angles)
DBC=28
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Answer:
The answer is 28
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