Question

ABCD is a rectangle with /_BAC=28° then /_CAD=?​

Answer 1

Answer:

62°.

Step-by-step explanation:

Property:

All angles of a triangle are equal to 90°.

Here,

/_ BAD = 90°. [By the above given property].

That is,

/_ BAC + /_ CAD = 90°.

So,

28° + /_ CAD = 90°.

/_ CAD = 90° - 28° = 62°.

Answer 2

$\therefore \angle CAD = 62 \degree$

Step-by-step explanation:

Rectangle

• Rectangle has 4 sides

• Opposite sides of rectangle are equal

• All angles of a rectangle are of 90°

___________________________

GIVEN

• ABCD is rectangle

• $\angle BAC = 28 \degree$

___________________________

TO FIND

$\angle CAD$

___________________________

We know that,

All angles of a rectangle are of 90°

Therefore,

$\angle BAC + \angle CAD = 90\degree$

$\therefore 28\degree + \angle CAD = 90\degree$

$\therefore \angle CAD = 90\degree - 28\degree$

$\therefore \angle CAD = 62 \degree$