Question

Abcd is a rectangle with ∠bac=42° determine ∠dbc

Answer 1

Answer:

Here is your answer... please mark me as the brainliest

Step-by-step explanation:

Suppose the diagonals AC and BD intersect at O.

Then, in∡ OAB, we have

OA = OB   [ diagonals of rectangle are equal and they bisect each other]

∠OAB = OBA

∠BAC = DBA

 ∠DBA = 32°          [BAC = 32°(given)]

Now,   ∠ABC = 90°

      ∠DBA +∠DBC = 90°

      32° + ∠DBC = 90°

        ∠DBC = 90° - 32° = 58°

therefore ∠DBC=58°

Answer 2

Answer:

48⁰

Step-by-step explanation:

let O intersect AC and BD

OAB =OBA

BAC =OBA

DBA = 42⁰( as BAC is 42⁰ given)

DBA +DBC = 90⁰

42⁰ + DBC = 90⁰

DBC = 48⁰