ABCD is a rectangle with diagonals AC and BD meeting at point 'O' find X if OA = 5x-7 and OD = 4x - 5
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In given figure ABCD is a rectangle.
⇒ OA=2x+4 and OD=3x+1 [Given]
⇒ AC and BD are diagonals of a rectangle.
⇒ We know that diagonals of rectangle are equal.
⇒ So, AC = BD
We can also write it as,
⇒ 2×OA=2×OD
⇒ $$2\times(2x+4)= 2\time (3x+1)
⇒ 2x+4=3x+1
∴ x=3
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Triangle AOB and triangle COD
AO = OC [ GIVEN ]
∠AOB = ∠COD [ VERTICALLY OPPOSITE ANGLES]
BO = OD [ GIVEN ]
So, triangle AOB is congruent to triangle COD [ SAS ]
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