ABCD is a rectangle with diagonals AC and BD meeting at O. if DAC = 50°, find the measure of each of the angles marked a, b, c,d,e,f,g
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<BAD = 90° (ABCD is a rectangle)
<CAD = <BAD-28
= 90 - 28 =
<CAD = 62°
Now,
In Triangle CAD and DBC
<ADC = <BCD (each 90°)
AD = BC (Opposite sides of rectangle)
CD =DC (common)
So, Triangle CAD congurent Triangle
DBC
(By S. A. S criteria)
<DBC = <CAD (C. P. C. T)
< DBC = 62°
= 62°
<OBC = 62°
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