Question

ABCD is a rectangle with dimensions 24 m by 16 m. AFE is a triangle such that EF ⊥ AD and EF = 10cm. Calculate the area of the shaded portion.

Answer 1

Step-by-step explanation:

Area of shaded portion = area of rectangle - area of ∆

$area = (24 \times 16) - ( \frac{1}{2} \times 16 \times 10$

$384 - 80$

$304m {}^{2}$

$answer..$

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Answer 2

Answer: 304 m²

Step-by-step explanation:

• Dimensions of Rectangle ABCD = 24 m by 16 m

• Area of Rectangle ABCD = 24 m * 16 m = 384 m² {Length*Breadth}

1. Dimensions of Triangle AFD =
2. Base = 16 m (Opp. sides of rectangle) {AD}
3. Height = 10 m (Given) {EF}

Area of Triangle AFD = 1/2 × 10 × 16  = 80 m²

We know that,

Area of the shaded region = Area of ABCD - Area of ∆AFD

                                            = 384 m² - 80 m²

                                            = 304 m²

Hence, the area of the shaded portion = 304 m²

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