ABCD is a rectangle with length AB = 13 cm and breadth CB = 7 cm. Point D is pushed towards point C to form parallelogram. Find the area of parallelogram ABCD.
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Answer: Area of parallelogram = 91 sq- cm
Solution:
Given that :ABCD is a rectangle with length AB = 13 cm and breadth CB = 7 cm
Since angles of rectangle are right angles,since breadth of rectangle is the perpendicular distance between side AB and CD
so, point D is only pushed to form a parallelogram,that means new figure so formed lie on same base and between the same parallels.
According to that theorem area of Rectangle = Area of Parallelogram
Area of rectangle = length × breadth
= 13 × 7 sq-cm
= 91 sq-cm
So area of parallelogram = 91 sq-cm
Hope it helps you.
Solution:
Given that :ABCD is a rectangle with length AB = 13 cm and breadth CB = 7 cm
Since angles of rectangle are right angles,since breadth of rectangle is the perpendicular distance between side AB and CD
so, point D is only pushed to form a parallelogram,that means new figure so formed lie on same base and between the same parallels.
According to that theorem area of Rectangle = Area of Parallelogram
Area of rectangle = length × breadth
= 13 × 7 sq-cm
= 91 sq-cm
So area of parallelogram = 91 sq-cm
Hope it helps you.
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