Question

ABCD is a rectangle, with M the midpoint of BC and N the midpoint of CD. If CM = 4 and NC = 5, what percent of the area of the rectangle is shaded?

Answer 1

Answer:

87.5%

Step-by-step explanation:

HELLO,

HERE IS YOUR ANSWER OF GIVEN QUESTION

IF THIS ANSWER HELPS YOU THEN I

REQUEST YOU TO MARK

IT BRAINLIST

Answer 2

percent of the area of the rectangle is shaded is 87.5 %

Step-by-step explanation:

given : ABCD is a rectangle, with M the midpoint of BC and N the midpoint of CD

CM = 4 and NC = 5

now, area of triangle NCM

$= \frac{1}{2}\times base \times height \\\\= \frac{1}{2}\times CN \times CM \\\\= \frac{1}{2}\times 5\times 4\\\\= 10 cm^2$

length of the rectangle =  10 cm

breadth of the rectangle = 8 cm

then

area of rectangle = length × breadth

area of rectangle = 10 ×8 = 80 cm²

area of the shaded region = area of rectangle - area of triangle

area of the shaded region = 80 - 10 = 70 cm ²

percentage of the shaded region = $\frac{\text{shaded portion}}{\text{complete rectangle }}\times 100$

= $\frac{70}{80}\times 100 = 87.5 %$

hence , percent of the area of the rectangle is shaded is 87.5 %

#Learn more :

In the given figure ABCD is a rectangle in which ab = to 40 cm and BC = 25 CM if pqrs be the midpoint of Ab BC CD and DA respectively as find the area of a shaded region

https://brainly.in/question/7977686