Question

ABCD is a rectangular form of a piece of paper, in which length AB = 22cm, breadth BC = 14cm. A semi-circular portion with BC as diameter is cut off from this piece. Find the area of the remaining portion.

Answer 1

Answer:

231 cm²

Step-by-step explanation:

At first, we will find the area of the rectangle : Length × Breadth

Now we will put the values as given in the question : 22×14 = 308 cm²

Now, we will find the area of semi circle :  πr² ×1/2

So, we will put values now : $\frac{22}{7} * 7*7*\frac{1}{2}$

So, After solving we get : 77 cm²

Now we will subtract it as it has been removed : 308 - 77 = 231 cm²

So, The area of the remaining portion is : 231 cm²

So, This is the correct method to do this question any quires just comment down below.

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