Math, asked by sanjaysaini0510, 5 hours ago

ABCD is a rectangular ground of length 40 m and breadth 30 m. Ramesh reached at C walking from A to B and B to C.But shyam reached to C walking from A to C directly.who walked the shorter distance and by how much?​

Answers

Answered by yashwanthkumar1590
0

Answer:

Ramesh travels short distance 70 m

Step-by-step explanation:

ABCD is a rectangle Ramesh travels from A to B and B to C that means

leanth AB=40 m

breadth BC= 30 m

total AB+BC =40+30=70 m

there fore Ramesh travel 70m

Shaun travel Directly A to C that means it in a diagonal

that means asume that, ABC IS a triangle

base AB=30 m and height BC=40 m

pythogerus theorem AC²=BC²+BA²

AC²=40²+30²

AC²=1600+900

AC²=2500

AC=√2500

AC=50

THERE FORE Shyam travels more than Ramesh.

please mark me as brainliest.

Answered by sabarishvijayakumar2
0

Answer:

hrhrhrhrhrhrhrhrhrhrhr

Similar questions