ABCD is a rectangular ground of length 40 m and breadth 30 m. Ramesh reached at C walking from A to B and B to C.But shyam reached to C walking from A to C directly.who walked the shorter distance and by how much?
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Answer:
Ramesh travels short distance 70 m
Step-by-step explanation:
ABCD is a rectangle Ramesh travels from A to B and B to C that means
leanth AB=40 m
breadth BC= 30 m
total AB+BC =40+30=70 m
there fore Ramesh travel 70m
Shaun travel Directly A to C that means it in a diagonal
that means asume that, ABC IS a triangle
base AB=30 m and height BC=40 m
pythogerus theorem AC²=BC²+BA²
AC²=40²+30²
AC²=1600+900
AC²=2500
AC=√2500
AC=50
THERE FORE Shyam travels more than Ramesh.
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