Question

ABCD is a regular parallelogram plot of land whose angle BAD
is 60°. If the bearing of the line AB is 30°, the bearing of CD, is​

Answer 1

Hi,

Answer:

The bearing of line CD is 210°.

Step-by-step explanation:

ABCD is given to be a regular parallelogram with angle BAD = 60°

The total interior angle of a parallelogram = (2n-4)*90

Where n = no. of sides of parallelogram = 4  

 

∴ The total interior angle = {(2*4) – 4} * 90 = 360°

So, the each included angle will be = 360°/ 4 = 90°

Now,  

Deflection angle = 180° - each included angle = 180° - 90° = 90°

Also, we know that

Fore bearing of any line =deflection angle + fore-bearing of the previous line …... (i)

And, we are given that

The fore bearing of line AB = 30° …. (ii)

Hence by using (i) & (ii) we can now traverse through each line of the parallelogram and calculate its fore bearings(F.B.):

∴ F.B. of BC = 90° + 30° = 120°

∴ F.B. of CD = 90° + 120° = 210°

And,  

∴ F.B. of DA = 90° + 210° = 300°

Hope this helps!!!!!

Answer 2

Answer:

210°

Step-by-step explanation:

<ABC=180°-60°=120°.

FB of AB=30°

BB of AB=30°+180°=210°

FB of BC=210°+<ABC=210°+120°=330°

BB of BC=330-180=150

FB of CD=150+<BAD=150+60=210°.