ABCD is a rhombus AB =26 and AC =48 find the angle between the diagonal AC and side AB
Answers
Answer:
BD is 20 cm
Step-by-step explanation:
ABCD is a rhombus
⇒ AB is the length of the side of the rhombus
⇒ AC is the diagonal of the rhombus
⇒ BD is the other diagonal of the rhombus
Find half of AC:
AC = 48
half of AB = 48 ÷ 2 = 24 cm
Find half of BD:
Half of BD, Half of AB and one side of the rhombus make a right angle triangle
a² + b² = c²
24² + b² = 26²
b² = 26² - 24²
b² = 100
b = √100
b = 10 cm
Find the length of BD:
BD = 2 x 10 = 20 cm
Answer: BD is 20 cm
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