Math, asked by ancelinrose123, 9 months ago

ABCD is a rhombus AB =26 and AC =48 find the angle between the diagonal AC and side AB​

Answers

Answered by krishnanageswaran
0

Answer:

BD is 20 cm

Step-by-step explanation:

ABCD is a rhombus

⇒ AB is the length of the side of the rhombus

⇒ AC is the diagonal of the rhombus

⇒ BD is the other diagonal of the rhombus

Find half of AC:

AC = 48

half of AB = 48 ÷ 2 = 24 cm

Find half of BD:

Half of BD, Half of AB and one side of the rhombus make a right angle triangle

a² + b² = c²

24² + b² = 26²

b² = 26² - 24²

b² = 100

b = √100

b = 10 cm

Find the length of BD:

BD = 2 x 10 = 20 cm

Answer: BD is 20 cm

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1

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