Question

ABCD is a rhombus. AC=10cm and BD=24cm .find the following : a) length of each side. b) perimeter of the rhombus

Answer 1

Step-by-step explanation:

as we know that diagonals of rhombus are perpendicular to each other

and thus as AC= 10cm and BD=24 cm

now let these diagonals meet at point O

now OA = 10/2 = 5 and OB = 24/2 = 12cm

now AB^2= OA^2 +OB^

so, AB^2 = (5)^2 + (12)^2

AB ^2 = 25+144 = 169

therefore, AB = 13 cm

now lengthy of each side is equal to 13 cm

and perimeter of a rhombus is equal to '4s'

now perimeter= 4× 13 = 52cm

Answer 2

Answer:

a) Length of each side is 10 , 24 , 12

b) Perimeter of all sides is 52.