Question

ABCD is a rhombus. ac=12,bd=16, find the area of quadrilateral by joining the mid point of rhombus ABCD​

Answer 1

Area of rhombus =

$\frac{1}{2} \times product \: of \: length \: of \: diagonals$

$\frac{1}{2} \times 12 \times 16 = 102 \: sq \: cm$