ABCD is a rhombus AC=12cm,BD=16.Find the area by joining the sides of rhombus
Answers
Answered by
5
hiiiiii
gd mrng.. ..
∆∆∆¶¶¶¶
To find the area of the rhombus is
1/2 x product of their diagonals...
the diagonals are AC and BD
AC = 12 CM
BD=16CM
¶¶¶¶¶ According to your question,
we have to find the area of the rhombus.
1/2 x AC xBD
. ¶1/2 x 12 x 16
¶ 1/2 x 192
¶ 192/2
¶. 92 squared cm..
________________________________________________________________________
HOPE THIS WILL HELP YOU ...
HAVE A NICE DAY......
gd mrng.. ..
∆∆∆¶¶¶¶
To find the area of the rhombus is
1/2 x product of their diagonals...
the diagonals are AC and BD
AC = 12 CM
BD=16CM
¶¶¶¶¶ According to your question,
we have to find the area of the rhombus.
1/2 x AC xBD
. ¶1/2 x 12 x 16
¶ 1/2 x 192
¶ 192/2
¶. 92 squared cm..
________________________________________________________________________
HOPE THIS WILL HELP YOU ...
HAVE A NICE DAY......
Answered by
3
Hello Dear!!!
Here's your answer....
By joining the sides....
We get the diagonals named AC and BD.
Given that,
AC = 12
BD= 16
The formula to find the area of the rhombus is
1/2 × AC × BD.
1/2 × 12 × 16.
96.
96cm^2 is the area of the rhombus.
________________________________
hope this helps you....
Here's your answer....
By joining the sides....
We get the diagonals named AC and BD.
Given that,
AC = 12
BD= 16
The formula to find the area of the rhombus is
1/2 × AC × BD.
1/2 × 12 × 16.
96.
96cm^2 is the area of the rhombus.
________________________________
hope this helps you....
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