ABCD is a rhombus. AC = 18cm, angle between BD and AB is
, such that
cos
=0.8. find diagonal BD and the perimeter of rhombus ABCD
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Answer:
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Step-by-step explanation:
Sosinθ=
AB
OB
⟹AB=
sinθ
OB
=
0.8
8
cm=10cm.
Again
AB
OA
=cosθ=0.6⟹OA=AB×0.6cm=10×0.6cm=6cm.
Butweknowthatthediagonalsofarhombusareright
bisectorofeachother.
∴AC=2AO=2×6cm=12cmand
BD=2OB=2×8cm=16cm.
∴Thesideoftherhombus=10cm.
Majordiagonal=16cm.
Minordiagonal=12cm.
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