Question

ABCD is a rhombus. AC is a diagonal. prove that AC devides rhombus ABCD into two congruent traingles.​

Answer 1

Answer:

Step-by-step explanation:

given

ABCD is a rhombus

AC is diagonal

R.T.P: triangle ACB is congruent to triangle ACD

in a rhombus opposite sides are equal to each other

therefore, ABCD is a parallelogram

In a parallelogram diagonal divides it into 2 congruent triangles .

therefore,triangle ACB is congruent to triangle ACD

Answer 2

Answer:

Given=ABCD is a rhombus

To prove =AC diagonal divide into two equal parts

Proof=Angle D=Angle B

Angle A=Angle C

AC is a common side

So,

By ASA

Tiangle ADC congruent to Triangle CBA

Hence proved