Question

ABCD is a rhombus ADB is 50 degree find the other angles of the rhombus.PLEASE RESPOND FAST
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Answer 1

Step-by-step explanation:

ABCD is a rhombus, so

AB = BC = CD = DA

AB || BC || CD || DA

In Δ ABD

AD = AB

angle ADB = angle ABD ( angle opposite to equal side are also equal)

angle ABD = 50°

angle ABD + angle ADB + angle DAB =180

50° + 50° + angle DAB = 180°

angle DAB = 180° - 100° = 80°

angle DAB = 80°

angle DAB = angle DCB (opposite angles)

angle DCB = 80°

angle DCB + angle CBA = 180° (co - interior angles)

angle CBA = 180 - 80 = 100°

angleCBA = 100°

angle CBA = angle ADC = 100°

So all angles of rhombus are :

angleABC = angleADC = 100°

angle DAB = angle DCB = 80°