ABCD is a rhombus and ABE is
an equilateral triangle. ZBCD = 78°. Calculate
ZADE, ZBDE and ZBED.
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Answer:
BAD=180−78=102
0
In triangle ABC, ∠BAC=∠BCA=51
0
[ABC is an isosceles triangle]
In triangle EDC, angle EDC is 60+78=138
0
So, ∠DCE=∠DEC=21
0
We know angle BCA is 102
0
Out of which angle BCA is 51 deg and angle DCE is 21 deg
Hence the remaining angle, angle ACE is 102−(51+21)=30
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∠DCE=21
0
∠ACE=30
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hope it helps u keep smiling :)
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