Question

ABCD is a rhombus and it's diagonals intersect at O . i) Is AOB ≈ BOC? Stata the congruence condition used. ii) Also, state of BCO = DCO. Deduce that each diagonal of a rhombus bisects the angles through which it passed.​

Answer 1

Answer:

1. in triangle AOB and BOC

AB =BC

AO =CO

OB =OB

triangle AOB congruent triangle BOC

by sss congruency

by cpct

2.BY CPCT

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Answer 2

Answer:

1) AOB=BOC

So, they are congruent .

SSS Property is applied

2) The diagonal is bisecting each other so the BCO=DCO

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