abcd is a rhombus and its diagonals intersect at o.
i) is ∆aob congruent to ∆boc ? state the congruence condition used.
ii)also state if angle BCO = angle DCO. Deduce that each diagonal of a rhombus bisects the angles through which it passes.
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(i)in triangle AOB and triangle BOC,
AB=BC( in rhombus all the sides are equal)
BO is the common side
angle AOB= angle BOC=90°
by RHS congruence,triangle AOB is congruent to triangle BOC
(ii) in triangle DOC and triangle BOC,
DC=BC( all sides are equal)
OC is common side
angle DOC = angle BOC=90°
therefore, by RHS congruence
triangle DOC is congruent to triangle BOC
therefore, angle DOC= angle BCO
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