Question

. ABCD is a rhombus and its two diagonals meet at
O, show that
AD sqare + DC sqare + CB sqare + BA sqare = 4 DOsqare + 4 AOsqare​

Answer 1

Answer:

LET AC AND BD INTERSECT AT A POINT O

IN TRIANGLE AOD

BY PYTHAGOROUS

AB^2 = AO^2 + DO^2

ON MULTIPLYING BY 4 ON BOTH SIDES

4AB^2.=4AO^2 + 4DO^2

ALL SIDES OF RHOMBUS ARE EQUAL SO---

AB^2 + BC^2 + CD^2 + DA^2 = 4AO^2 +4 DO^2

Step-by-step explanation:

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