Question

abcd is a rhombus . angle bac=43° find angle acb and angle dac

please answer it!​

Answer 1

Answer:

all angles 43 degrees

Step-by-step explanation:

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Answer 2

Answer:

ABCD is Rhombus (Given)

AB = BC

∠BAC = ∠ACB (∠s opp. to equal sides)

But ∠BAC = 43° (Given)

∠ACB = 43°

In ∆ABC,

∠ABC + ∠BAC + ∠ACB = 180°

∠ABC + 43°+ 43° = 180°

∠ABC = 180° – 86° = 94°

But ∠ABC = ∠ADC (opp. ∠s of rhombus)

∠ADC = 94°

∠DAC = ∠DCA ( AD = CD)

∠DAC = 1/2 [180° – 94°]

∠DAC = 1/2 x 86° = 43°

Hence (i) ∠ACB = 43° (ii) ∠DAC = 43° (iii) ∠ADC = 94°

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