Question

abcd is a rhombus angle CAB =36° find angle DBA..
plzzz solve it ...​

Answer 1

Answer:

54°

hope it helps u........

Answer 2

Step-by-step explanation:

In triangles abc and acd,

bc = ad [opposite sides of a rhombus]

ac is common to both

ab = dc [opposite sides of a rhombus]

therefore,

triangle abc is congruent to triangle acd

=> angle bca = angle acd

but angle bca = 36°

therefore, angle c = angle bca + angle acd

= 36° + 36° [angle bca = angle acd]

= 72°

now in rhombus abcd,

angle a = angle c [opposite angles of rhombus]

angle a = 72°

Also,

angle bac = angle dac

but angle bac + angle dac = angle a

=> angle bac + angle bac = angle a

[angle bac = angle dac]

=>2 × angle bac = angle a

=> angle bac = 72° / 2

=> angle bac = 36°

In triangle abc,

by angle sum property,

angle bac + angle bca + angle abc = 180°

=> 36° + 36° + angle abc = 180°

=> 72° + angle abc = 180°

=> angle abc = 180°-72°

=> angle abc = 108°

or angle b = 108°

therefore angle b = angle d = 108 °

[opposite angles of a rhombus]

therefore angle adc = 108°

[angle adc is same as angle d]