Question

abcd is a rhombus bybjoining the mid point of the sides of a quadrilateral pqrs if area of pqrs is 96cm square then area of abcd is​

Answer 1

Area of rhombus abcd = 48$cm^{2}$

Given that;

Area of quadrilateral = 96$cm^{2}$

To find;

The area of Rhombus abcd

Solution;

We know that,

The triangle inscribed in a parallelogram is half of the area of the parallelogram.

Therefore, Area of triangle abd = 1/2 Area of pqbd

and the area of triangle bcd = 1/2 x area of brsd

Area of abd + Area of bcd = 1/2 x Area of pqbd +  1/2 x Area of brsd

Area of abcd = 1/2 x Area of brsd + 1/2 x Area of pqbd

Area of abcd = 1/2 x Area of pqrs

therefore, Area of abcd = 1/2 x 96$cm^{2}$

Area of rhombus abcd = 48$cm^{2}$

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