Math, asked by rsytudgcihkvhkvoj, 4 months ago

ABCD is a rhombus, EABF is a straight line such that EA=AB=BF. Prove that ED and FC when produced meet at right angles.

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Answered by Anonymous

13

$\huge{\fcolorbox{white}{pink}{Answer:}}$

♡We know that the diagonals of a rhombus are perpendicular bisector to each other.

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