Question

ABCD is a rhombus,EABF is a straight line such that EA=AB=BF. Prove that ED and FC when produced meet at right angle.

Answer 1

Answer:

Step-by-step explanation:

heya..

here is your answer..

SinceΔEAD=ΔABC

(Corresponding angles),&AD=BC(sides of the rhombus)

By side angle side congrugency,the triangles

Therefore the corresponding parts of the triangle are also equal.

ΔCBF & ΔDAB

Since the sides 

BF=AB

∠CBF∠DAB(corresponding angles)

ΔCBF&ΔDAB are congrugent

ΔAOB

∠ABO+∠BAO+∠AOB=180°

∠ABO+∠BAO=90°

∠CFB+∠AED=90°

∠XFE+∠XEF=90°

it may help you...

Answer 2

Answer:

Hope it helps you

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