Abcd is a rhombus, find the values of a,b and c
please jaldii batao..
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From the figure,ABCD is a rhombus
Then, the diagonals of rhombus bisect each other at right angles.
So,AO=OC
x=8cm
Therefore, AO=8cm
And BO=OD
y=6cm
Therefore, BO=6cm
Consider the ΔAOB, it is a right angled triangle.
By Pythagoras theorem,
AB
2
=AO
2
+BO
2
AB
2
=8
2
+6
2
AB
2
=64+36
AB
2
=100
AB=
100
AB=10cm
Answered by
1
Answer:
as the diagonals of the rhombus intersect each other at mid point so,
a=15
b=8
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