abcd is a rhombus If Ac=8cm and BD=6cm find the lenght of the side of the
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Here is your solution
GIVEN :-
abcd IS A RHOMBUS
so,
ab=bc=cd=ad
ac = 8 cm
bd = 6 cm
Now,
we know that In rhombus diagonal bisect each other at center and 90° formation also.
oa = oc = 4cm
ob = od = 3cm
Now,
In right △ boc
\begin{gathered}ob{}^{2} + oc {}^{2} = bc {}^{2} \\ \\( 3cm) {}^{2} + (4cm) {}^{2} = bc{}^{2} \\ \\ 9cm {}^{2} + 16cm {}^{2} = bc {}^{2} \\ \\ 25cm {}^{2} = bc {}^{2} \\ \\ \sqrt{25cm {}^{2} } = bc \\ \\ 5cm = bc\end{gathered}
ob
2
+oc
2
=bc
2
(3cm)
2
+(4cm)
2
=bc
2
9cm
2
+16cm
2
=bc
2
25cm
2
=bc
2
25cm
2
=bc
5cm=bc
Note:-
all sides of rhombus is equal .
so all sides of rhombus is 5 cm
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