Question

ABCD is a rhombus if angle ACB=40 then angle ADB?????

Answer 1

congurent triangle ADC and triangle BCD then by CPCT angle c =angle d so angle D =40

Answer 2

Answer:

Step-by-step explanation:

Given ABCD is a rhombus. Diagonals bisect each other perpendicularly. Hence ∠BOC = 90° Given ∠OCB = 40° AD||BC and BD is the transversal ∴ ∠ADB = ∠DBC (Alternate angles) Hence in right angled DBOC, ∠BOC + ∠OCB + ∠OBC = 180° ⇒ 90° + 40° + ∠OBC = 180° ⇒130° + ∠OBC = 180° ⇒ ∠OBC = 180° - 130° = 50° But ∠OBC = ∠DBC Therefore, ∠ADB = 50°

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