Question

abcd is a rhombus. If angle bac is 38 find angle acb ,dac and adc

Answer 1

ABCD is Rhombus (Given)

AB = BC

∠BAC = ∠ACB (∠s opp. to equal sides)

But ∠BAC = 38° (Given)

∠ACB = 38°

In ∆ABC,

∠ABC + ∠BAC + ∠ACB = 180°

∠ABC + 38°+ 38° = 180°

∠ABC = 180° – 76° = 104°

But ∠ABC = ∠ADC (opp. ∠s of rhombus)

∠ADC = 104°

∠DAC = ∠DCA ( AD = CD)

∠DAC = 1/2 [180° – 104°]

∠DAC = 1/2( 76°) = 38°

Hence (i) ∠ACB = 38° (ii) ∠DAC = 38° (iii) ∠ADC = 104°.

make it brainliest

hope it is helpful .....